[" 36.If the area enclosed between the "],[y=kx^(2)" and "x=ky^(2),(k>0)" ,is "1" squater "],[" Then "k" is "]

If the area enclosed between the curves y=kx^(2) and x=ky^(2), where k>0, is 1 square unit.Then k is: (a) (1)/(sqrt(3)) (b) (sqrt(3))/(2) (c) (2)/(sqrt(3))(d)sqrt(3)

If the area enclosed between the curves y=kx^2 and x=ky^2 , where kgt0 , is 1 square unit. Then k is: (a) 1/sqrt(3) (b) sqrt(3)/2 (c) 2/sqrt(3) (d) sqrt(3)

If the area enclosed between the curves y=kx^2 and x=ky^2 , where kgt0 , is 1 square unit. Then k is: (a) 1/sqrt(3) (b) sqrt(3)/2 (c) 2/sqrt(3) (d) sqrt(3)

If the area enclosed between the curves y=kx^2 and x=ky^2 , where kgt0 , is 1 square unit. Then k is: (a) 1/sqrt(3) (b) sqrt(3)/2 (c) 2/sqrt(3) (d) sqrt(3)

If the area enclosed between the curves |y | =1-x^(2) and x^(2)+ y^(2) =1 is (3pi -K)/( 8) sq. unit ,then the value of K is equal to-

Using integration, find the area enclosed between the curve y^(2) =2x+1 , and the x-y-1=0

The angle between the lines 3x-y-1=0 and 2x+ky+5=0 is 45^(@) find k

Let A(k) be the area bounded by the curves y=x^(2)+2x-3 and y=kx+1. Then

Let A(k) be the area bounded by the curves y=x^(2)+2x-3 and y=kx+1. Then