" 86"quad a+b+c=0quad (a^(2))/(bc)+(b^(2))/(ca)+(c^(2))/(ab)

If a , b , c are all non-zero and a+b+c=0 , then (a^(2))/(bc)+(b^(2))/(ca)+(c^(2))/(ab)= ? .

If a+b+c = 0 find (a^(2))/(bc) + (b^(2))/(ca) + (c^(2))/(ab)= ?

If a+b+c=0, then find the value of (a^(2))/(bc)+(b^(2))/(ca)+(c^(2))/(ab)

If a+b+c=0, the value of ((a^(2))/(bc)+(b^(2))/(ca)+(c^(2))/(ab)) is

If a+b+c=0, then write the value of (a^(2))/(bc)+(b^(2))/(ca)+(c^(2))/(ab)

If ab + bc + ca = 0, then what is the value of (a^(2))/(a^(2) - bc) + (b^(2))/(b^(2)-ca) + (c^(2))/(c^(2) - ab) ?

Ifa+b+c=0, findthevalue ((b+c)^(2))/(bc)+((c+a)^(2))/(ca)+((a+b)^(2))/(ab)