Home
Class 10
MATHS
The sum of the first 3 consecutive terms...

The sum of the first 3 consecutive terms of an increasing AP is `51` and the product of the first and third term of this AP is `273`, then the third term is

Text Solution

Verified by Experts

Let these three terms are, `a-d,a and a+d`.
Then,
`a-d+a+a+d = 51=> 3a = 51=> a = 17`
Now, `(a-d)(a+d) = 273`
`=>(17-d)(17+d) = 273`
`=>289-d^2 = 273=> d^2 = 16`
`=> d = 4` (As d can not be negative.)
...
Promotional Banner

Similar Questions

Explore conceptually related problems

If the sum of three consecutive terms of an increasing A.P. is 51 and the product of the first and third of these terms is 273, then the third term is (a) 13 (b) 9 (c) 21 (d) 17

If the sum of three consecutive terms of an increasing A.P. is 51 and the product of the first and third of these terms is 273, then the third term is (a) 13 (b) 9 (c) 21 (d) 17

The sum of the first three terms of an Arithmeic Progression (A.P.) is 42 and the product of the first and third term is 52. Find the first term and the common difference.

The sum of the third and seventh terms of an AP is 6 and their product is 8 find the sum of first sixteen terms of the A.P.

The sum of four consecutive terms of an A.P is 32. The product of the second and the third term is 60. Find these terms.

The sum of the third and seventh terms of an A.P is 6 and their product is 8 find the sum of first sixteen terms of the A.P.

The sum of the third and the seventh terms of an AP is 6 and their product is 8. find the sum of first sixteen terms of the AP.

The sum of three terms of an A.P. is 21 and the product of the first and the third terms exceeds the second term by 6, find three terms.

The sum of three terms of an A.P. is 21 and the product of the first and the third terms exceeds the second term by 6, find three terms.