Home
Class 12
PHYSICS
The most abundant isotope of helium has ...

The most abundant isotope of helium has a `._(2)^(4)H` nucleus whose mass is `6.6447 xx 10^(-27) kg` . For this nucleus, find (a) the mass defect and (b) the binding energy.
Given: Mass of the electron: `m_e =5.485799 xx 10^(-4) u`, mass of the proton: `m_(P) =1.007276 u` and mass of the neutron: `m_(n) =1.008 665 u`.

Promotional Banner

Similar Questions

Explore conceptually related problems

The atomic mass of B^(10) is 10.811 amu . Find the binding energy of B^(10) nucleus . The mass of electron is 0.0005498 amu. The mass of proton is m_(p) = 1.007276 amu . The mass of neutron is m_(n) = 1.008665 amu.

The binding enrgy of ._(17)^(35)Cl nucleus is 298 MeV. Find the atomic mass. Given, mass of a proton (m_(P))=1.007825 amu, mass of a neutron (m_(n))=1.008665 amu.

Calculate The binding energy per nucleon of ._(6)^(12)C nucleus. Nuclear mass of ._(6)^(12)C=12.000000 u , mass of proton = 1.007825 u and mass of neutron = 1.008665 u.

Calculate the (i) mass defect, (ii) binding energy and (iii) the binding energy per nucleon of ""_(6)^(12)C nucleus. Nuclear mass of ""_(6)^12C = 12. 000000 u, mass of proton=1.007825 u and mass of neutron=1.008665 u.

What is the binding energy per nucleon of _(6)C^(12) nucleus? Given , mass of C^(12) (m_(c))_(m) = 12.000 u Mass of proton m_(p) = 1.0078 u Mass of neutron m_(n) = 1.0087 u and 1 amu = 931.4 MeV

What is the binding energy per nucleon of _(6)C^(12) nucleus? Given , mass of C^(12) (m_(c))_(m) = 12.000 u Mass of proton m_(p) = 1.0078 u Mass of neutron m_(n) = 1.0087 u and 1 amu = 931.4 MeV