A tangent PT is drawn to the circle `x^2+y^2=4` at point `p(sqrt3, 1)` A straight line L perpendicular to PT is a tangent to the circle `(x-3)^2 + y^2 =1` A possible equation of `L` is

A Tangent PT is drawn to the circle x^2 + y^2 =4 at point p( sqrt(3) ,1). A straight line L perpendicular to PT is a tangent to the circle (x-3)^2 +y^2=1 A possible equation of L is

A tangent PT is drawn to the circle x^(2)+y^(2)=4 at point p(sqrt(3),1) A straight line L perpendicular to PT is a tangent to the circle (x-3)^(2)+y^(2)=1 A possible equation of L is

A tangent PT is drawn to the circle x^2+y^2 =4 at the point P(sqrt3,1) . A straight line L, perpendicular to PT is a tangent to the circle. (x - 3)^2+ y^2 = 1 A possible equation of L is

A tangent PT is drawn to the circle x^2 + y^2= 4 at the point P(sqrt3,1) . A straight line L is perpendicular to PT is a tangent to the circle (x-3)^2 + y^2 = 1 Common tangent of two circle is: (A) x=4 (B) y=2 (C) x+(sqrt3)y=4 (D) x+2(sqrt2)y=6

A tangent PT is drawn to the circle x^2 + y^2= 4 at the point P(sqrt3,1). A straight line L is perpendicular to PT is a tangent to the circle (x-3)^2 + y^2 = 1 Common tangent of two circle is: (A) x=4 (B) y=2 (C) x+(sqrt3)y=4 (D) x+2(sqrt2)y=6

A tangent PT is drawn to the circle x^2+y^2 =4 at the point P(sqrt3,1) . A straight line L, perpendicular to PT is a tangent to the circle. (x - 3)^2+ y^2 = 1 A common tangent of the two circles is

A tangent PT is drawn to the circle x^2+y^2=4 at the point P(sqrt3,1) . A straight line L , perpendicular to PT is a tangent to the circle (x-3)^2+y^2=1 then find a common tangent of the two circles

A tangent PT is drawn to the circle x^2+y^2=4 at the point P(sqrt3,1) . A straight line L , perpendicular to PT is a tangent to the circle (x-3)^2+y^2=1 then find a common tangent of the two circles