" 17.If "Delta ABC sim Delta PQR" and "(BC)/(QR)=(2)/(3)" then find "(ar(Delta PQR))/(ar(Delta ABC))

It is given that Delta ABC~Delta PRQ and (BC)/(QR)=(2)/(3) " then " (ar (Delta PQR))/(ar (Delta ABC))=?

If Delta ABC ~ Delta PQR with (BC)/(QR) = 1/3 , then find (ar Delta PRQ)/(ar Delta BCA) ?

It is given that Delta ABC - Delta PQR , with (BC)/(QR) = (1)/(4) . Then (ar Delta PQR)/(ar Delta ABC) is equal to:

If triangle ABC - triangle PQR and (BC)/(QR) = 1/4 then (ar(trianglePQR))/(ar(triangleABC)) =

If Delta ABC ~ Delta PQR , then find /_ B .

Delta ABC ~ Delta PQR and ar(DeltaABC)=4ar(DeltaPQR) IF BC=12cm then find QR

If Delta ABC ~ Delta PQR and 4A (Delta ABC) = 25 A (Delta PQR) then AB : PQ = ?

The base BC of Delta ABC is divided at D, so that BD=(1)/(2)DC. Prove that ar(Delta ABD)=(1)/(3)ar(Delta ABC)

In Figure 1,PQ|BC and AP:PB=1:2* find the ratio of (ar Delta APQ)/(ar Delta ABC)

Given triangle ABC ~ triangle PQR if (AB)/(PQ)=1/3 then find (ar triangle ABC)/(ar triangle PQR)