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The emf of the cell, Ni | Ni^(2+) (1.0M)...

The emf of the cell, `Ni | Ni^(2+) (1.0M) || Ag^(+)(1.0M)` [`E^(@) for Ni^(2+)//Ni = -0.25 volt, E^(@) for Ag^(+)//Ag = volt)` is given by:

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The emf of the cell, Ni|Ni^(2+)(1.0M)||Ag^(+)(1.0M)|Ag [E^(@) for Ni^(2+)//Ni =- 0.25 volt, E^(@) for Ag^(+)//Ag = 0.80 volt] is given by : [E^(@) for Ag^(+)//Ag = 0.80 volt]

The emf of the cell, Ni|Ni^(2+)(1.0M)||Ag^(+)(1.0M)|Ag [E^(@) for Ni^(2+)//Ni =- 0.25 volt, E^(@) for Ag^(+)//Ag = 0.80 volt] is given by : [E^(@) for Ag^(+)//Ag = 0.80 volt]

The emf of the cell, Ni|Ni^(2+)(1.0M)||Ag^(+)(1.0M)|Ag [E^(@) for Ni^(2+)//Ni =- 0.25 volt, E^(@) for Ag^(+)//Ag = 0.80 volt] is given by : [E^(@) for Ag^(+)//Ag = 0.80 volt]

emf of cell Ni, Ni^(2+)(1.0M) || Au^(3+)(1.0M), Au is …………If E^@ for Ni^(2+)|Ni is 0.25V, E^@ for Au^(3+)| Au is 1.50 V.

The emf of the cell: Ni//Ni^(2+) (1.0 M)//Au^(3+) (1.0M)//Au (E^(@) = -0.25V " for " Ni^(2+)//Ni and E^(@)= 1.5V "for " Au^(3+)//Au) is