" (x) "(x^(2)-2x+24)/(x^(2)-3x+4)<=4

Solve: (x^(2)-2x+24)/(x^(2)-3x+4)<=4

Solve: (x^2-2x+24)/(x^2-3x+4)lt=4 .

The sum of all possible solution (s) of the equation |x+2|-3|=sgn(1-|((x-2)(x^(2)+10x+24))/((x^(2)+1)(x+4)(x^(2)+4x-12))|)

If f(x) is continuous at x=-2 , where f(x)=(2)/(x+2)+(1)/(x^(2)-2x+4)-(24)/(x^(3)+8) , for x!= -2 , then f(-2)=

(x^2+x-6)(x^2-3x-4)=24

x ^ (3) + 5x ^ (2) -2x-24, x ^ (3) -4x ^ (2) + x + 6

(x^(4)+24x^(2)+28)/((x^(2)+1)^(3))=

Factorise each of the following polynomials using synthetic division: (i) x^(3) -3x^(2) -10x +24 (ii) 2x^(3) -3x^(2) -3x +2 (iii) -7x +3+4x^(3) (iv) x^(3) +x^(2) -14x -24 (v) x^(2) - 7x+ 6 ( vi ) x^(3) -10x ^(2) -x+ 10