`int_0^pilog(1+cosx)dx` .

int_0^pi log(1+cosx)dx

Evaluate the following integral: int_0^pilog(1-cos x)dx

Evaluate the following integral: int_0^pilog(1-cos x)dx

Evaluate: int_0^pi log(1+cosx)dx

Evaluate: int_0^pi log(1+cosx)dx

Evaluate: int_0^pi log(1+cosx)dx

The value of the integral int_(0)^(pi)log(1+cosx)dx is a) (pi)/(2)log2 b) -pilog2 c) pi log2 d)None of these

Find I=int_0^pi ln(1+cosx)dx

Find I=int_0^pi ln(1+cosx)dx

int_0^pi dx/(1+cosx)