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The figure shows two regions in the firs...

The figure shows two regions in the first quadrant. `P(t, sin t^2) `the curve `B(t),A(t)` is the area under the curve `y = sin x^2` from `0` to `t` and `B(t)` is the area of the triangle with vertices ` P` and `M(t,0)`. Find `Lim _(t->0)A(t)/B(t)`

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The figure shows two regions in the first quadrant.For curve y=sin x^(2),A(t) is the area under the curve y=sin x^(2) from 0 to t and B(t) is the area of the triangle with vertices O(0,0),P(t,sin t^(2)) and M(t,0) Find lim(t rarr0)(A(t))/(B(t))

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