Two identical non-re,aticivistic particles move at right angle to each other. Possesing de Broglie wavelength `lambda_(1)` and `lambda_(2)` Find the Broglie wavelength of each particle in the frame of their centre of inertia.

Two identical non-relativitic partcles A and B move at right angles to each othre, processing de Broglie wavelengths lamda_1 and lamda_2 , respectively. The de Broglie wavelength of each particle in their centre of mass frame of reference is

The de Broglie wavelength lambda of a particle

Two electrons are moving with non-relativistic speeds perpendicular to each other. If corresponding de Broglie wavelengths are lambda_(1) and lambda_(2) their the Brogile wavelength in the frame of reference attached to their centre of mass is :

In what way de - Broglie wavelength lambda of a particle is related to K.E?

The de Broglie wavelength (lambda) of a particle is related to its kinetic energy E as

A particle is moving with kinetic energy E. It's de Broglie wavelength is—

Two particles move at right angle to each other.Their de Broglie wavelengths are lambda_(1) and lambda_(2) respectively.The particles suffer perfectly inelastic collision.The de Broglie wavelength lambda of the final particle is given by :

de Broglie wavelength of a moving particle is lambda . Its momentum is given by :