Simplify: `sin(x+alpha) sin(x-alpha)`

sin 3 alpha = 4 sin alpha sin(x + alpha) sin(x-alpha)

If sin 3alpha = 4 sin alpha sin (x + alpha)sin(x-alpha) , then x =

If sin 3 alpha =4 sin alpha sin (x+alpha ) sin(x-alpha ) , then

If sin 3 alpha =4 sin alpha sin (x+alpha ) sin(x-alpha ) , then

If sin 3 alpha =4 sin alpha sin (x+alpha ) sin(x-alpha ) , then

If sin 3 alpha =4 sin alpha sin (x+alpha ) sin(x-alpha ) , then

If sin 3 alpha =4 sin alpha sin (x+alpha ) sin(x-alpha ) , then

Find the general solution of the equation sin 3 alpha = 4 sin alpha sin(x + alpha) sin(x - alpha) , given sin alpha ne 0 .

sin3 alpha=4sin alpha sin(x+alpha)sin(x-alpha)