if `ax^2+bx+c = 0` has imaginary roots and `a+c lt b` then prove that `4a+c lt 2b`

if ax^(2)+bx+c=0 has imaginary roots and a+c

If y=f(x)=ax^(2)+2bx+c=0 has Imaginary roots and 4a+4b+c<0 then

If ax^(2)+bx+c=0 has imaginary roots and a,b,c in Rsuch that a+4c<2b then

If the equation cx^(2)+bx-2a=0 has no real roots and a lt (b+c)/(2) then

If ax^2 + bx + c = 0, a, b, c in R has no real zeros, and if a + b + c + lt 0, then

If the equation ax^(2) + 2 bx - 3c = 0 has no real roots and (3c)/(4) lt a + b , then

The roots of the equation ax^2+bx + c = 0 will be imaginary if, A) a gt 0 b=0 c lt 0 B) a gt 0 b =0 c gt 0 (C) a=0 b gt 0 c gt 0 (D) a gt 0, b gt 0 c =0