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[" 8).The least resolvable angle by a te...

[" 8).The least resolvable angle by a telescope using "],[" objective of aperture "5m" is nearly "],[(lambda=4000A^(0))^(0)-(1*22)/(a)lambda=(1*22times4times10^(-7))/(5)],[" 1) "(1)/(50^(0))" 2) "(1)/(50)" minute "(3)(1)/(50)secquad 4" ) "(1)/(500)sec]

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The least resolvable angle by a telescope using objective of aperture 5 m is nearly (lambda = 400 Å)

What is the resolving power of a telescope whose objective lens has a diameter 1.22 m from a wavelength 4000 Å?

A: To increase resolving power of a telescope, the diameter of objective should be large. R: Resolving power of a telescope is given by (D)/(1.22 lambda)

[[1,0,-13,4,50,-6,-7]]=[[(1)/(10),(3)/(10),(1)/(5)(21)/(20),-(7)/(20),-(2)/(5)-(9)/(10),(3)/(10),(1)/(5)]]

If A=[(1,0),(1/2,1)] then A^50 is (A) [(1,25),(0,1)] (B) [(1,0),(25,1)] (C) [(1,0),(0,50)] (D) [(1,0),(50,1)]

If A=[(1,0),(1/2,1)] then A^50 is (A) [(1,25),(0,1)] (B) [(1,0),(25,1)] (C) [(1,0),(0,50)] (D) [(1,0),(50,1)]

If the rank of the matrix [(lambda,-1,0),(0, lambda,-1),(-1,0,lambda)] is 2, then find lambda .