A capillary tube of radius 1 mm is dipped in water of surface tension 0.073 N `m^(-1)`. Find the weight of water that rises in the tube. Take angle of contact `theta = 0^(@)`
Hint : `h rho g = (2 S cos theta)/(2)`
Required wt = `pi r^(2) h rho g`

A capillary tube of radius 0.5 mm is dipped vertically in a liquid of surface tension 0.04 N/m and relative density 0.8 g/cc . Calcukate the height of capillary rise , if the angle of contact is 10^@ .

If the surface tension of water is 0.06 Nm^(-1) , then the capillary rise in a tube of diameter 1 mm is (angle of contact = 0^@ ) ………….. .

A capillary tube of radius 0.5 mm is dipped in a vessel containing water. Calculate the height to which water will rise in the capillary tube. Take, surface tension of water =7.4 xx 10^(-3)" N/m".

When a capillary tube of radius 'r' is dipped vertically in a liquid of surface tension T, the liquid rises to a height 'h' in the tube above the level outside the tube. If the angle of contact is theta , the density of the liquid is rho , then the pressure difference is.

When a capillary tube of radius r is dipped vertically in a liquid of surface tension T, the liquid rises to a height h in the tube above the level outside the tube . If the angle of contact is theta the density of the liquid is rho then the pressure difference between the points A and B is

If surface tension of water is 0.07 N/m the weight of water supported in a capillary tube of radius 0.1 mm is