The ratio of accleration due to gravity at a depth h below the surface of earth and at a height h above the surface of earth for h `lt lt` radius of earth:

Find the expression of acceleration due to gravity at a high h above the surface of the earth.

The ratio of acceleration due to gravity at a height 3 R above earth's surface to the acceleration due to gravity on the surface of earth is (R = radius of earth)

The ratio of acceleration due to gravity at a height 3 R above earth's surface to the acceleration due to gravity on the surface of earth is (R = radius of earth)

The ratio of acceleration due to gravity at a height 3 R above earth's surface to the acceleration due to gravity on the surface of earth is (R = radius of earth)

Imagine earth to be a solid sphere of mass M and radius R. If the value of acceleration due to gravity at a depth d below earth's surface is same as its value at a height h above its surface and equal to (g)/(4) (where g is the value of acceleration due to gravity on the surface of earth), the ratio of (h)/(d) will be

The acceleration due to gravity at a height 1 km above the earth is the same as at a depth d below the surface of earth

Imagine Earth to be a solid sphere. If the value of acceleration due to gravity at a depth 'd' below Earth's surface is the same as its value at a height 'h' above its surface and is equal to g/4 then the ratio of h/d will be ......

The acceleration due to gravity at a height 1km above the earth is the same as at a depth d below the surface of earth. Then :

The acceleration due to gravity at a height 1km above the earth is the same as at a depth d below the surface of earth. Then :