[" 6.In Fige "6.37" ,if "Delta ABE-=Delta ACD" ,threw that "],[/_ADE-/_ABC]

In Fig. 6.37, if Delta ABE~=Delta ACD , show that Delta ADE~Delta ABC .

In that figure, if Delta ABE ~= Delta ACD , show that Delta ADE ~= Delta ABC .

In Fig. If Delta ABE = ACD , show that Delta ADE ~ Delta ABC .

AD BE and CF are the medians of a Delta ABC .Prove that 2(AD+BE+CF)<3(AB+BC+CA)<4(AD+BE+CF)

For Delta ABC , find the measure of angle ACD .

If AD and PM are median of triangles ABC and PQR respectively where Delta ABC - Delta PQR , prove that (AB)/(PQ) = (AD)/(PM) .

AD and PM are medians of triangles ABC and PQR respectively where Delta ABC ~ Delta PQR . Prove that: (AB)/(PQ)=(AD)/(PM) .

ABC is an isosceles triangle with AB=AC and D is a point on ABC BC such that AD_|_BC (see figure ). To prove that angleBAD =angleCAD a student proceeded as follows In Delta ABD and Delta ACD ,we have AB=AC " " [" Given"] angleB=angleC " "[because AB=AC ] and " "angleADB= angleADC Therefore " " DeltaABD cong Delta ACD " " ["by AAS congruence rule"] So , " "angleBAD =angleCAD " " [by CPCT] What is the defect in the above argument ?

ABC is an isosceles triangle with AB=AC and D is a point on ABC BC such that AD_|_BC (see figure ). To prove that angleBAD =angleCAD a student proceeded as follows In Delta ABD and Delta ACD ,we have AB=AC " " [" Given"] angleB=angleC " "[because AB=AC ] and " "angleADB= angleADC Therefore " " DeltaABD cong Delta ACD " " ["by AAS congruence rule"] So , " "angleBAD =angleCAD " " [by CPCT] What is the defect in the above argument ?