[x cos((y)/(x))(ydx+xdy),=y sin((y)/(2))(sin y-y)],[y,=vx,y=y]

Solve the following differential equation, x cos ((y)/(x)) (ydx + xdy) = y sin ((y)/(x)) (xdy- ydx)

Solve the following differential equation: x cos((y)/(x))ydx+xdy=sin((y)/(x))xdy-ydx

IF x cos ( y //x ) ( ydx + xdy)=y sin ( y // x) ( xdy - ydx ) y (1) = 2 pi then the value of 4 ( y (4) )/(pi ) cos (( y (4))/(4)) is :

IF x cos ( y //x ) ( ydx + xdy)=y sin ( y // x) ( xdy - ydx ) y (1) = 2 pi then the value of 4 ( y (4) )/(pi ) cos (( y (4))/(4)) is :

Show that the given differential equation is homogeneous and solve each of them.{x cos((y)/(x))+y sin((y)/(x))}ydx={y sin((y)/(x))-cos((y)/(x))}xdy

Solve {x cos((y)/(x))+y sin((y)/(x))}ydx={y sin((y)/(x))-x cos((y)/(x))}xdy

The general solution of the differential equation x.cos(y/x)(ydx+xdy)=y sin(y/x)(xdy-ydx) is (A) xy=c sec((x)/(y)) (B) y=xc sec((x)/(y)) (C) xy=c sec((y)/(x)) (D) None of these

The solution of cos((x)/(y))(ydx-xdy)=xy^(3)(xdy+ydx) is sin((x)/(y))=((xy)^(lambda))/(mu)+C then the value of (lambda+mu) is

Obtain the particular solution of the differential equation: { x cos ((y)/( x)) + y sin ((y)/( x))} ydx= { y sin ((y)/( x) ) - x cos ((y)/( x))}xdy where : x=2 when y= (pi)/(2) .