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|[2a,a-b-c,2a],[2b,2b,b-c-a],[c-a-b,2c,2...

|[2a,a-b-c,2a],[2b,2b,b-c-a],[c-a-b,2c,2c]|=(a+b+c)^(3)

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Prove: |[a-b-c,2a,2a],[2b,b-c-a,2b],[2c,2c,c-a-b]|=(a+b+c)^3

Prove: |[a-b-c,2a,2a],[2b,b-c-a,2b],[2c,2c,c-a-b]|=(a+b+c)^3

Show that: |[a-b-c,2a,2a],[2b,b-c-a,2b],[2c,2c,c-a-b]|=(a+b+c)^3

Prove that: |[a-b-c, 2a,2a],[2b,b-c-a,2b],[2c,2c,c-a-b]|=(a+b+c)^3

Solve the determinant using properties |[a-b-c,2a,2a],[2b,b-c-a,2b],[2c,2c,c-a-b]| = (a+b+c)^3

Using properties of determinants prove the following. abs[[a-b-c,2a,2a],[2b,b-c-a,2b],[2c,2c,c-a-b]]=(a+b+c)^3

Prove that abs[[a-b-c,2a,2a],[2b,b-c-a,2b],[2c,2c,c-a-b]]=(a+b+c)^3