A point moves linearly with deceleration which is given by `dv//dt=-alphasqrt(v)`, where alpha is a positive constant. At the start `v=v_(0)`. The distance traveled by particle before it stops will be

A point moves rectilinearly with deceleration whose modulus depends on the velocity v of the particle as alpha=ksqrtv , where k is a positive constant. At the initial moment the velocity of the point is equal to V_0 . What distance will it take to cover that distance?

A point moves rectilinearly with deceleration whose modulus depends on the velocity v of the particle as alpha=ksqrtv , where k is a positive constant. At the initial moment the velocity of the point is equal to V_0 . What distance will it take to cover that distance?

A point moves rectilinearly with deceleration whose modulus depends on the velocity v of the particle as w=asqrtv , where a is a positive constant. At the initial moment the velocity of the point is equal to v_0 . What distance will it traverse before it stops? What time will it take to cover that distance?

A point moves rectilinearly with deceleration which depends on the velocity v of the particle as a = k sqrtv , where is apositive constant. At the initial moments the velocity of the point is equal to v_(0) . What distance will it cover before it stops, and what time it will take to cover that distance.

A point moves rectilinearly with deceleration whose modulus depends on the velocity v of the paticles as alpha=ksqrt(v) , where k is a positive constant .At the initial movement the velocity of the point in equal to V_(0) . What distance will it take to cover that distance?

A point moves rectilinearly with deceleration whose modulus depends on the velocity v of the paticles as alpha=ksqrt(v) , where k is a positive constant .At the initial movement the velocity of the point in equal to V_(0) . What distance will it take to cover that distance?