`A B C` is a triangle and `A=(235)dotB=(-1,3,2)a n dC=(lambda,5,mu)dot` If the median through `A` is equally inclined to the axes, then find the value of `lambdaa n dmudot`

A B C is a triangle and A=(2,3,5),B=(-1,3,2) and C= (lambda,5,mu). If the median through A is equally inclined to the axes, then find the value of lambda and mu

A B C is a triangle and A=(2,3,5),B=(-1,3,2) and C= (lambda,5,mu). If the median through A is equally inclined to the axes, then find the value of lambda and mu

A B C is a triangle and A=(2,3,5),B=(-1,3,2) and C= (lambda,5,mu). If the median through A is equally inclined to the axes, then find the value of lambda and mu

ABC is a triangle and A=(2,3,5),B=(-1,3,2) and C=(lambda,5,mu). If the median through A is equally inclined to the axes,then find the value of lambda and mu

ABC is a triangle in a plane with vertices A(2,3,5),B(-1,3,2) and C(lambda,5,mu) ,If the median through A is equally inclined to the coordinates axes then the value of (lambda^(3)+mu^(3)+5) is

ABC is a triangle in a plane with vertices A(2,3,5),B(-1,3,2) and C(lamda,5,mu) . If the median through A is equally inclined to the coordinate axes, then the value of lamda^(3)+mu^(3)+5 is

A B C is a triangle where A=(2,3,5)B=(-1,2,2)a n dC(lambda,5mu) , if the median through A is equally inclined to the axes then: lambda=mu=5 (b) lambda=5,mu=7 lambda=6,mu=9 (d) lambda=0,mu=0

In DeltaABC , A(2,3,5), B(-1,3,2) and C(lambda,5,mu) . If the median through A is equally inclined to the axes, then find the value of lambda and mu . a) 10,7 b) 9,10 c) 7,9 d) 7,10

ABC is a triangle in a plane with vertices A(2, 3, 5), B(-1, 3, 2) and C(lambda, 5, mu) . If the median through A is equally inclined to the coordinate axes, then the value of (lambda^(3)+mu^(3)+5) is:

ABC is a triangle where A=(2,3,5)B=(-1,2,2) and C(lambda,5 mu) if the median through A is equally inclined to the axes then: lambda=mu=5 (b) lambda=5,mu=7lambda=6,mu=9(d)lambda=0,mu=0