SHM given by `x= 6 sin omega t + 8 cos omega t ` . Its amplitude is

The displacement of a particle executing a S.H.M. is given by x= A "sin" omega t +A "cos" omega t . What is the amplitude of motion ?

The SHM of a particle is given by the equation x=2 sin omega t + 4 cos omega t . Its amplitude of oscillation is

The SHM of a particle is given by the equation x=2 sin omega t + 4 cos omega t . Its amplitude of oscillation is

The displacement of a SHM particle is y= 3 sin omega t+4 cos omega t then its amplitude will be……

The displacement of a particle executing simple harmonic motion is given by y= A_(0) +A sin omega t+ B cos omega t . Then the amplitude of its oscillation is given by:

The displacement equation of a particle of medium during wave mation is given by y=A sin omega t-B cos omega t The amplitude of the oscillator will be

x = A cos omega t + B sin omega t , the amplitude of this wire is:

The rms value of emf is given by E (8 sin omega t + 6 cos omega t) volt is

The displacement of a particle performing simple harmonic motion is given by, x=8 "sin" "omega t + 6 cos omega t, where distance is in cm and time is in second. What is the amplitude of motion?

Two simple harmonic motions are given by x_(1) = a sin omega t + a cos omega t and x_(2) = a sin omega t + (a)/(sqrt3) cos omega t The ratio of the amplitudes of first and second motion and the phase difference between them are respectively