The reaction , `X + 2Y + Z rarr N` occurs by the following mechanism
(i) `X+Y hArr M` (very rapid equilibrium)
(ii) `M + Z rarr O` (slow)
(iii) `O + Y rarr N` (very fast)
What is the rate law for this reaction

The reaction A+2B+C to Z occurs by the following mechanism: (i) A+2B+C to X (fast) (ii) X+C to Y (slow) (iii) Y+B to Z (very fast) Rate law for this reaction is:

A following mechanism has been proposed for a reaction 2A +B rarr D rarr E A+ B rarrC+D (slow) A+C rarr E (fast) The rate law expression for the reaction by RDS methd is:

A following mechanism has been proposed for a reaction 2A +B rarr D rarr E A+ B rarrC+D (slow) A+C rarr E (fast) The rate law expression for the reaction by RDS methd is:

A following mechanism has been proposed for a reaction 2A +B rarr D rarr E A+ B rarrC+D (slow) A+C rarr E (fast) The rate law expression for the reaction by RDS methd is:

The mechanism of the reaction: A + 2B + C rarr D is (step 1) (fast) equilibrium A+B hArr X (step 2)(slow) X + C rarr Y (step 3) (fast) Y + B rarr D Which rate law is correct ?

In the formation of HBr form H_(2) and Br_(2) , following mechanism is observed: I. Br_(2) hArr 2Br^(*) (Equilibrium step) (II) H_(2) + Br^(*)rarr HBr+H^(*) (Slow step) (III) H^(*) + Br_(2) rarr HBr + H^(*) (Fast step) The rate law for the above reaction is