The area of the parallelogram constructed on the vectors `veca=vecp+2vecq` and `vecb=2vecp+vecq` as sides`vecp,vecq` are unit vectors.Find their area

Consider a parallelogram constructed on the vectors vecA=5vecp+2vecq and vecB=vecp-3vecq . If |vecp|=2, |vecq|=5 , the angle between vecp and vecq is (pi)/(3) and the length of the smallest diagonal of the parallelogram is k units, then the value of k^(2) is equal to

Consider a parallelogram constructed on the vectors vecA=5vecp+2vecq and vecB=vecp-3vecq . If |vecp|=2, |vecq|=5 , the angle between vecp and vecq is (pi)/(3) and the length of the smallest diagonal of the parallelogram is k units, then the value of k^(2) is equal to

For any two vectors vecp and vecq , show that |vecp.vecq| le|vecp||vecq| .

For any two vectors vecp and vecq , show that |vecp.vecq| le|vecp||vecq| .

if vecP +vecQ = vecP -vecQ , then

if vecP +vecQ = vecP -vecQ , then

Given that veca and vecb are unit vectors. If the vectors vecp=3veca-5vecb and vecq=veca+vecb are mutually perpendicular, then

Consider the vector vecp=2i-j+k . Find two vectors vecq and vecr such that vecp,vecq and vecr are mutually perpendicular.

Given that vecp=veca+vecb and vecq=veca-vecb and |veca|=|vecb|, show that vecp.veca=0

Given that vecp=veca+vecb and vecq=veca-vecb and |veca|=|vecb| , show that vecp.vecq=0