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Each of the strings of length 51.6 cm an...

Each of the strings of length `51.6 cm` and `49.1 cm` are tensioned separately by `20 N` force. Mass per unit length of both the strings is the same and equal to `1gm^(-1)`. When both the strings vibrate simultaneoulsy the number of beats is

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Each of the two strings of length 51.6 cm and 49.1 cm are tensioned separately by 20 N force. Mass per unit length of both the strings is same and equal to 1 g//m . When both the strings vibrate simultaneously, the number of beats is

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A string 50 cm long is under a tension of 20N force. Caculate the frequency of fundamental mode given that mass of the string is 1 g.

A string 50 cm long is under a tension of 20N force. Caculate the frequency of fundamental mode given that mass of the string is 1 g.