When radiation is incident on a photoelectron emitter, the potential is found to be 9V. If `e//m` for the electron is `1.8cc10^(11)C//kg`, the maximum velocity of the ejected electron is

When radiation is incident on a photoelectron emitter , the stopping potential is found to be 9 volts . If e//m for the electrons is 1.8 xx 10^(11) C kg^(-1) the maximum velocity of the ejected electrons is

When radiation is incident on a photoelectron emitter , the stopping potential is found to be 9 volts . If e//m for the electrons is 1.8 xx 10^(11) C kg^(-1) the maximum velocity of the ejected electrons is

Radiation is incident on a photosensitive surface and the stopping potential is found to be 9 V. What is the maximum velocity of the ejected photo electrons if the specific charge of the electron is 1.8xx10^(11) C/kg ?

An electron is accelerated through a potential difference of 200 volts. If e//m for the electron be 1.6 xx 10^(11) coulomb/kg, the velocity acquired by the electron will be

An electron is accelerated through a potential difference of 200 volts. If e//m for the electron be 1.6 xx 10^(11) coulomb/kg, the velocity acquired by the electron will be

The work function for calcium is 2.14 eV. When a light of wavelength 5500Å is incident on it, photoelectrons are emitted , Calculate (i) threshold frequency and threshold wavelength. (ii) maximum velocity of the emitted electrons. (iii) change in maximum kinetic energy of the emitted photoelectrons if the intensity of the incident light is doubled. Take : h = 6.6 xx10^(-34) Js m_e-9xx10^(-31) kg c= 3xx10^8m//s

For two monochromatic radiations incident on the same metal surface, the stopping potentials are 1.0 V and 2.0 V. The ratio between the maximum velocities, of the emitted photoelectrons is

In an electron gun, the electrons are accelerated by the potential V . If the e is the charge and m is the mass of the electron, then the maximum velocity of these electrons will be

In an electron gun, the electrons are accelerated by the potential V . If the e is the charge and m is the mass of the electron, then the maximum velocity of these electrons will be

if e/m of electron is 1.76xx10^(11)C(kg)^(-1) andn stopping potential is 0.71 V, then the maximum velocity of the photoelectron is