A particle is moving in a circular path of radius a under the action of an attractive potential `U=-(k)/(2r^(2))`. Its total energy is :

A particle is moving in a circular path of radius a under the action of an attraction potential U = - (k)/(2r^(2)) . Its total energy is

A particle is moving in a circular path of radius a under the action of an attractive potential U = -k/(2r^(2)) .Its energy is

A particle is moving in a circular path of radius r under the action of a force F. If at an instant velocity of particle is v, and speed of particle is increasing, then

A particle is moving along a circular path of radius of R such that radial acceleration of particle is proportional to t^(2) then

A particle of mass M moves with constant speed along a circular path of radius r under the action of a force F. Its speed is

A particle of mass M moves with constant speed along a circular path of radius r under the action of a force F. Its speed is