Let `A = {(x, y) : x, y in R, x^2 + y^2 = 1}` and `B = {(x, 0) :x in R,-1<= x <=1}`, then the elements of `A nn B` can be

Let P={(x,y)//x in R, y in R, x^(2)+y^(2)=1} , then P is

If A = {(x, y) : y^2 = x, x, y in R} , B = {(x, y) : y = |x|, x, y in R} , then

Which one of the following is not a function? {(x , y): x , y in R , x^2=y} b. {(x , y): x , y in R , y^2=x} c. {(x , y): x , y in R , x=y^3} d. {(x , y): x , y in R , y=x^3}

If A = {(x, y) : x^2 = y, x, y in R} B = {(x, y) : y = |x|, x, y in R} then

Let A ={(x,y) in R xx R: y = 5^(x) + 12^(x)} B = {(x,y) in R xx R , y = 13^(x)} Then

A = {(x,y) : y = 1//x,0 ne x in R} , B = {(x, y) : y = - x, x in R} then