For the reaction , `A+2B hArr 2C`, the rate constant for the forward and the backward reactions are `1xx10^(-4)` and `2.5xx10^(-2)` respectively.The value of equilibrium constant, K, for the reaction would be :

For the reaction, A(g)+2B(g) hArr 2C(g) , the rate constant for forward and the reverse reactions are 1xx10^(-4) and 2.5xx10^(-2) respectively. The value of equilibrium constant, K for the reaction would be

For the reaction, A(g)+2B(g) hArr 2C(g) , the rate constant for forward and the reverse reactions are 1xx10^(-4) and 2.5xx10^(-2) respectively. The value of equilibrium constant, K for the reaction would be

For the reaction A+B hArr C , the rate constants for the forward and the reverse reactions are 4xx10^(2) and 2xx10^(2) respectively. The value of equilibrium constant K for the reaction would be

For the reaction A+B hArr C , the rate constants for the forward and the reverse reactions are 4xx10^(2) and 2xx10^(2) respectively. The value of equilibrium constant K for the reaction would be

For the reaction, A_(g) + 2B_(g) iff 2C_(g) , the rate constants for the forward and the reverse reactions are 1 xx 10^-4 and 2.5 xx 10^-2 respectively. The value of equilibrium constant, K for the reaction would be

For an equilibrium reaction, the rate constants for the forward and the backward reaction are 2.38xx10^(-4) and 8.15xx10^(-5) , respectively. Calculate the equilibrium constant for the reaction.

For an equilibrium reaction, the rate constants for the forward and the backward reaction are 2.38xx10^(-4) and 8.15xx10^(-5) , respectively. Calculate the equilibrium constant for the reaction.

The rate constans of forward and backward reactions are 8.5 xx 10^(-5) and 2.38 xx 10^(-4) respectively. The equilibrium constant if