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In the given figure A B is the diameter ...

In the given figure `A B` is the diameter of the circle, centred at `Odot` If `/_C O A=60^0,A B=2r ,A C=d ,` and `C D=l` , then l is equal to `dsqrt(3)` (b) `d//sqrt(3)` `3d` (d) `sqrt(3)` d /2

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