AB is a diameter of a circle. CD is a chord parallel to AB and `2CD = AB`. The tangent at B meets the line AC produced at E then AE is equal to -

AB is a diameter of a circle with centre at O. If chord CD bot AB and angleCAD = 80^@ , then angleADC =

In the adjoinig figure, AB is a diameter of the circle, CD is a chord equal to the radius of the circle. AC and BD when extended intersect at a point E. Prove that angleAEB=60^@ .

In the adjoinig figure, AB is a diameter of the circle, CD is a chord equal to the radius of the circle. AC and BD when extended intersect at a point E. Prove that angleAEB=60^@ .

In Figure, AB is a diameter of the circle, CD is a chord equal to the radius of the circle. AC and BD when extended intersect at a point E. Prove that /_A E B = 60^@

AB is a diameter of a circle with centre O and AC is a chord . The straight line through O parallel to AC meets the arc BC at D. Prove that, BD= CD.

The given figure shows, AB is a diameter of the circle. Chords AC and AD produced meet the tangent to the circle at point B in points P and Q respectively. Prove that: AB^2 = AC xxAP

AB is the diameter and AC is a chord of a circle with centre O such that angle BAC=30^(@) . The tangent to the circle at C intersects AB produced in D. Show that BC=BD.