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Tangents are drawn to the circle x^2+y^2...

Tangents are drawn to the circle `x^2+y^2=50` from a point "P lying on the x-axis. These tangents meet the y-axis at points `'P_1,' and 'P_2`. Possible co-ordinates of 'P' so that area of triangle `PP_1P_2` is minimum is/are -

Text Solution

Verified by Experts

Equation of tangent to the given circle will be:
`y=mx+(5sqrt2)(sqrt(1+m^2)) => (1)`
It passes through the point P(p,o),so
`0=mp+(5sqrt2)(sqrt(1+m^2))`
We get,
`m=sqrt(50/(p^2-50))`
For P1,
`y=m*0+(5sqrt2)(sqrt(1+m^2))` ...
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