QUESTION-9 Slope of a line passing through P(2.3) and intersecting the line x+y=7 at a distance of 4 units from P. is: [JEE-MAINS 2019||

If a line is passing through p(2,3) which intersects the line x+y=7 at a distance of four units from P. Then the slope of line is

The slope of line passing through A(2, 3), B(4,7)

A line passing through A(1, -2) has slope 1. The points on the line at a distance of 4sqrt(2) unit from A are

The slope of the line passing through A(-2,3) is -4/3 .The points on the line that are 10 units away from A are

A line passing through P(1,2) intersect the line x+y+3=0 in point A such that AP=3sqrt(2) then slope of AP is

The equation of the line passing through the point of intersection of the lines 2x+y-4=0, x-3y+5 =0 and lying at a distance of sqrt5 units from the origin, is

The equation of the line passing through the point of intersection of the lines 2x+y-4=0, x-3y+5 =0 and lying at a distance of sqrt5 units from the origin, is

The vertical straight line passing through the point of intersection of the straight lines x-3y+1=0, 2x+5y-9=0 and at a distance of 2 units from the origin has the equation

Find the equation of a line passing through the intersection of the lines y=2(x-1) and y=3x-5 and which is at a distance of (7)/(sqrt(2)) units from origin.