[20=(2^(n))=(2^(40))^(10+0)" (0) None of these "],[[" (B) "2^(39)+^(40)C_(20)," (C) "2^(39)-(1)/(2)*^(40)C_(20)," (D) "2^(39)+(1)/(2),4^(40)C_(20)]]

The sum ""^(40)C_(0) + ""^(40)C_(1)+""^(40)C_(2)+…+""^(40)C_(20) is equal to

The sum ""^(40)C_(0) + ""^(40)C_(1)+""^(40)C_(2)+…+""^(40)C_(20) is equal to

[(2,-1),(3,-2)]^(n)=[(1,0),(0,1)] if n is

The angles of a triangle are (x-40)^(0),(x-20)^(0) and ((1)/(2)x-10)^(0) .find the value of x

Value of cot40^(0)cot20^(0)(4sin10^(0)-1) is -1 (b) 1 (c) 2 (d) 0

Statement - 1: The value of ((20),(0))((20),(1))-((20),(1))((20),(9))+((20),(2))((20),(8))-((20),(3))((20),(7))+...+((20),(10))((20),(0))=0, where ((n),(r))=^nC_r Statement - 2: .^nC_0-^nC_1+^nC_2-^nC_3+...+(-1)^n .^nC_n=0.

int_(0)^(10 pi)(|sin x|+|cos x|)dx is equal to (A) 20(C)10(B)40(D) none of these

If [(x,1)][(1,0),(-2,0)] = 0, then x equals