A gas containining hydrogen-like ions, with atomic number `Z`, emits photons in transition `n + 2 to n, where n = Z` These photons fall on a metallic plate and eject electrons having minimum de Broglie wavelength `lambda of 5 Å`. Find the value of `Z` , if the work function of metal is `4.2 eV`

A gas containing hydrogen like atoms with atomic number Z, emit photons in transition n+2ton, where n=Z and work function of metal is 4.2eV . The photons are incident on the metal emitting electrons of minimum de Broglie wavelength 5A^(0)

An electron in Li^(2+) ion makes a transition from higher state n_(2) to lower state n_(1)=6. The emitted photons is used to ionize an electron in H-atom from 2nd excited state. The electron on leaving the H-atom has a de Broglie wavelength lambda-12.016 "Å" .Find the value of n_(2). Note : Use (12.016)^(2)= (150xx144)/(13.6xx11),lambda_("Å")=sqrt((150)/(KE_(eV)))

An electron in Li^(2+) ion makes a transition from higher state n_(2) to lower state n_(1)=6. The emitted photons is used to ionize an electron in H-atom from 2nd excited state. The electron on leaving the H-atom has a de Broglie wavelength lambda-12.016 "Å" .Find the value of n_(2). Note : Use (12.016)^(2)= (150xx144)/(13.6xx11),lambda_("Å")=sqrt((150)/(KE_(eV)))

What is the wavelength of a photon emitted during a transition from n = 5 state to the n = 2 state in the hydrogen atom

Light emitted by hydrogen gas corresponding to transition from n= 3 to n=2 incident on a metal plate.The electron emitted from metal plate with maximum kinetic energy enters a magnetic field 5 xx 10^-4T perpendicularly. If the radius of path of electron is 7 mm then find the work function of metal.

A glass tube has Be^(+++) ions excited to their second excited state. The radiation coming out of this tube is incident on a metal plate having work function f = 5 eV . Find the minimum de-Broglie wavelength of emitted photoelectrons.

Electrons in a sample of gas containing hydrogen-like atom (Z = 3) are in fourth excited state. When photons emitted only due to transition from third excited state to second excited state are incident on a metal plate photoelectorns are ejected. The stopping potential for these photoelectorns is 3.95 eV . now, if only photons emitted due to transition from fourth excited state to third excited state are incident on the same metal plate, the stopping potential for the emitted photoelectrons will be appoximetely equal to

A photon of energy 2.5 eV and wavelenght lambda falls on a metal surface and the ejected electron have velocity 'v' . If the lambda of the incident light is decreased by 20% the maximum velocity of the emitted electrons is doubled. The work function of the metal is

What are the frequency and wavelength of a photon emitted during a transition from n = 5 state to the n = 2 state in the hydrogen atom?