[" 7."96sqrt(3)sin(pi)/(48)*cos(pi)/(48)*cos(pi)/(24)*cos(pi)/(12)*cos(pi)/(6)],[" has the value "]

96 sqrt3 sin(pi/48) cos(pi/48) cos(pi/24) cos(pi/12) cos(pi/6) has the value

The value of 64sqrt(3)sin((pi)/(48))cos((pi)/(48))cos((pi)/(24))cos((pi)/(12))cos((pi)/(6))

Prove that 32 (sqrt(3)) sin"" (pi)/(48) cos"" (pi)/(48) cos"" (pi)/(24) cos"" (pi)/(12) cos"" (pi)/(6) = 3

The value of sin(pi/48)cos(pi/48)cos(pi/24)cos(pi/12)cos(pi/6)cos(pi/3) is:

(sin((5pi)/12)-cos((5pi)/12))/(cos((5pi)/12)+sin((5pi)/12))=

sin ""(pi)/(4) cos ""(pi)/(12) - cos ""(pi)/(4) sin ""(pi)/(12) is equal to

sin((7pi)/(12))cos(pi/4)-cos((7pi)/(12))sin(pi/4)=...........

cos""(pi)/(7)+cos""(2pi)/(7)+cos""(3pi)/(7)+......cos""(6pi)/(7)=?