[" (ii) "quad (-2,0),(0,4),(0,k)],[" ines determinants."]

Find the value of k,if area of triangle is 4 sq. units and vertices arw (k,0),(4,0) and(0,2) using determinant.

If area of the triangle with vertices (-2, 0), (0, 4) and (0, k) is 4 square units, find the value of 'k' using determinants.

If the area of the triangle with vertices (-2, 0) (0, 4) and (0,k) is 4 square units. Find the value of k using determinants.

If the area of the triangle with vertices (-2, 0), (0, 4) and (0, k) is 4 square units, find the values of k u"sin"g determinants.

If the area of the triangle with vertices (-2,0) ( 0,4) (0,k) having 4 sq. units then K=

if A = [(2,4),(-1,k)], and A^(2) = [(0,0),(0,0)] find the value of k.

Find the values of 'k' if area of the triangle is 4 square unts and vertices are (2,0),(0,4),(0,k) .

The area of a triangle with vertices (-2,0),(0,k) and (0,4) is 4 square units.Then the values of K will be

If area of triangle is 4 sq. units with vertices (-2, 0), (0, 4) and (0, k) then k is :