[" Perpendiculars are drawn from angles "A,B" and "C" of an acute angled triangle on the opposite "],[" sides and produced to meet the circumscribing circles.If these produced parts be "alpha,beta," and "gamma],[" respectively,then show that "(a)/(alpha)+(b)/(beta)+(c)/(gamma)=2(tan A+tan B+tan C)]

Perpendiculars are drawn from the angles A,B and C of an acute-angled triangle onthe opposite sides,and produced to meet the circumscribing circle.If these produced parts are alpha.,beta,gamma, respectively,then show that, then show that then show that (a)/(alpha)+(b)/(beta)+(c)/(gamma)=2(tan A+tan B+tan C)

Perpendiculars are drawn from the angles A, B and C of an acute-angled triangle onthe opposite sides, and produced to meet the circumscribing circle. If these produced parts are alpha., beta, gamma, respectively, then show that, then show that a/alpha+b/beta+c/gamma=2(tanA+tanB+tanC).

Perpendiculars are drawn from the angles A, B and C of an acute-angled triangle onthe opposite sides, and produced to meet the circumscribing circle. If these produced parts are alpha., beta, gamma, respectively, then show that, then show that a/alpha+b/beta+c/gamma=2(tanA+tanB+tanC).

Perpendiculars are drawn from the angles A, B and C of an acute-angled triangle onthe opposite sides, and produced to meet the circumscribing circle. If these produced parts are alpha., beta, gamma, respectively, then show that, then show that a/alpha+b/beta+c/gamma=2(tanA+tanB+tanC).

perpendiculars are drawn from the angles A , Ba n dC of an acute-angled triangle on the opposite sides, and produced to meet the circumscribing circle. If these produced parts are alpha,beta,gamma , respectively, then show that a/alpha+b/beta+c/gamma=2(tanA+tanB+t a nC)dot

Perpendiculars are drawn from the anglesA, B,C,of an acute angles Delta on the opposite sodes and products to meet the circumscribing circle. If these produced parts be propto,beta,gamma respectively, show that (a)/prop+(b)/beta+(c)/gamma=2(tanA+tanB+tanC

If a right angle be divided into three parts alpha, beta and gamma , prove that cot alpha = (tan beta + tan gamma)/(1-tan beta tan gamma) .

If a right angle be divided into three parts alpha,beta and gamma, prove that cot alpha=(tan beta+tan gamma)/(1-tan beta tan gamma)

If a right angle be divided into three parts alpha,beta and gamma, prove that cot alpha=(tan beta+tan gamma)/(1-tan beta tan gamma)

If alpha,beta,gamma are acute angle such that cos alpha=tan beta,cos beta=tan gamma and cos gamma=tan alpha then