the equation of a wave on a string of linear mass density `0.04 kgm^(-1)` is given by
`y = 0.02(m) sin[2pi((t)/(0.04(s)) -(x)/(0.50(m)))]`.
Then tension in the string is

The equation of a wave on a string of linear mass density 0.04 kg m^(-1) is given by y = 0.02 (m) sin [2pi((t)/(0.04(s))-(x)/(0.50(m)))] . The tension in the string is :

The equation of a wave on a string of linear mass density 0.04 kg m^(-1) is given by y = 0.02 (m) sin [2pi((t)/(0.04(s))-(x)/(0.50(m)))] . The tension in the string is :

The equation of a transverse wave along a stretched string is given by y = 15 sin 2pi ((t)/(0.04) - (x)/(40)) cm . The velocity of the wave is

The equation of a transverse wave propagating through a stretched string is given by y=2 sin 2pi ((t)/(0.04) -x/(40)) where y and x are in centimeter and t in seconds. Find the velocity of the wave, maximum velocity of the string and the maximum acceleration.

A transverse periodic wave on a string with a linear mass density of 0.200 kg/m is described by the following equation y=0.05 sin (420t-21.0 x) where x and y are in metres and t is in seconds.The tension in the string is equal to :

A transverse periodic wave on a string with a linear mass density of 0.200 kg/m is described by the following equation y=0.05 sin (420t-21.0 x) where x and y are in metres and t is in seconds.The tension in the string is equal to :

A transverse periodic wave on a string with a linear mass density of 0.200 kg//m is described by the following equation y = 0.05 sin(420t - 21.0 x) where x and y are in meters and t is in seconds. The tension in the string is equal to :

The equation of a progressive wave is given by, y = 3 sin pi ((t)/(0.02) - (x)/(20)) m . Then the frequency of the wave is