Home
Class 11
PHYSICS
[" For a particle acceleration is define...

[" For a particle acceleration is defined as "vec a=(-5timeshat i)/(|x|)" for "x!=0" and "vec a=0" for "x=0." If the particle is "],[" initially at rest at "(a,0)," what is period of motion of the particle."],[[" (A) "4sqrt(2a/5)sec" (B) "8sqrt(2a/5)sec.," (C) "2sqrt(2a/5)" sec."," (D) cannot be determined "],[" Part of a simple harmonic motion is granhed in the forme "]]

Promotional Banner

Similar Questions

Explore conceptually related problems

If a particle is moving as vec(r) = ( vec(i) +2 vec(j))cosomega _(0) t then,motion of the particleis

If a particle is moving as vec(r) = ( vec(i) +2 vec(j))cosomega _(0) t then,motion of the particleis

The acceleration of particle at position x is given by a=3-2x. If the particle is rest at x=0, at what value of x is it at rest again ?

The velocity of a particle moving in the positive direction of the x axis varies as v=5sqrtx , assuming that at the moment t=0 the particle was located at the point x=0 , find acceleration of the particle.

V_(x) is the velocity of a particle of a particle moving along the x- axis as shown. If x=2.0m at t=1.0s , what is the position of the particle at t=6.0s ?

V_(x) is the velocity of a particle of a particle moving along the x- axis as shown. If x=2.0m at t=1.0s , what is the position of the particle at t=6.0s ?

V_(x) is the velocity of a particle of a particle moving along the x- axis as shown. If x=2.0m at t=1.0s , what is the position of the particle at t=6.0s ?

A particle is performing non UCM, the acceleration of the particle is veca_(R)=veca_(r)+veca_(T) , where vec a_(r) is radial component of acceleration. If veca_(r)=0 , the motion of the particle is

A particle executes the motion described by x(t) = x_0 (1-e^(-gammat) , t le 0, x_0 > 0 . Where does the particle start and with what velocity?