A particle is at rest at `x=a`. A force `vecF=(b)/(x^(2))veci`
begins to act on the particle. The particle starts its motion, towards the origin, along X-axis. Find the velocity of the particle, when it reaches a distance x from the origin .

A particle starts from the origin with a velocity of 2cm/s and moves along a straight line.If the acceleration of the particle at a distance xcm from the origin be (2x-(3)/(2))(cm)/(s^(2)), find the velocity of the particle at a distance 7cm from the origin.

A particle starts from rest x = - 2.25 m and moves along the x - axis with the v - t graph as shown. The time when the particle crosses the origin is :

The velocity-time graph of a particle in straight line motion is velocity-time graph of a particle in straight line motion is shown in. The particle starts its motion from origin. . The distance of the particle from the origin after 8 s is .

A particle starts from rest at the origin and moves along the positive x direction. Its acceleration a versus position x graph is shown in the figure. The velocity of the particle at x = 6 m is?

A particle is kept at rest at the origin. A constant force rarrF starts acting on it at t = 0 . Find the speed of the particle at time t.

A particle is kept at rest at the origin. A constant force rarrF starts acting on it at t = 0 . Find the speed of the particle at time t.

In the figure a graph is plotted which shows the variation of the x- component of a force that acts on a particle moving along the x-axis, with x. The particle starts from rest from the origin. Then

Three particles start from the origin at the same time, one with velocity u_1 along the x-axis, the second with velocity u_2 along the y-axis . Find the velocity of the third particles, along the x=y line so that the three particles may always lie on the same straight line.

Instantaneous velocity of a particle moving in +x direction is given as v = (3)/(x^(2) + 2) . At t = 0 , particle starts from origin. Find the average velocity of the particle between the two points p (x = 2) and Q (x = 4) of its motion path.

A particle is projected with velocity V_(0) along axis x . The deceleration on the particle is proportional to the square of the distance from the origin i.e., a=omegax^(2). distance at which the particle stops is