If `y_1, y_2, y_3` be the ordinates of a vertices of the triangle inscribed in a parabola `y^2=4a x ,` then show that the area of the triangle is `1/(8a)|(y_1-y_2)(y_2-y_3)(y_3-y_1)|dot`

If y_(1),y_(2),y_(3) be the ordinates of a vertices of the triangle inscribed in a parabola y^(2)=4ax then show that the area of the triangle is (1)/(8a)|(y_(1)-y_(2))(y_(2)-y_(3))(y_(3)-y_(1))|

If y_(1),y_(2) and y_(3) are the ordinates of the vertices of a triangle inscribed in the parabola y^(2)=4ax then its area is

If y_(1),y_(2),andy_(3) are the ordinates of the vertices of a triangle inscribed in the parabola y^(2)=4ax , then its area is

If y_(1),y_(2),andy_(3) are the ordinates of the vertices of a triangle inscribed in the parabola y^(2)=4ax , then its area is

If y_(1),y_(2),andy_(3) are the ordinates of the vertices of a triangle inscribed in the parabola y^(2)=4ax , then its area is

If 2,4,8 are the ordinates of the vertices of a triangle inscribed in the parabola y^(2)=8x ,then area of triangle is

The area of the triangle inscribed in the parabola y^(2)=4x the ordinates of whose vertices are 1,2 and 4 is

The area of the triangle inscribed in the parabola y^(2)=4x the ordinates of whose vertices are 1, 2 and 4 square units, is

y_(1) and y_(2) and y_(3) are the ordinates of three points on the parabola y ^(2) = 4ax, then the area of the triangle formed by the points is-