Express `1/(1+cos theta-i sin theta)` in the form of `a +ib`.

Express (1)/(1-cos theta+2i sin theta) in the form of a+ib .

Express (1)/(1-cos theta+2i sin theta) in the form x+iy.

Solve (1)/(cos theta-i sin theta)

1 + cos theta + i sin theta | =?

Express (cos theta - sin theta)" in the form " r cos (theta+ alpha) and (sqrt 3sin theta + cos theta) " in the form r" sin(theta + beta).

We express ((cos 2theta -i sin 2theta)^(4) (cos 4theta + i sin 4 theta)^(-5))/((cos 3theta + i sin 3theta)^(-2) (cos 3theta -i sin 3theta)^(-9)) in the form of x+iy , we get

The argument of 1-cos theta-i sin theta is

If we express ((cos 2 theta-i sin 2 theta)^(4)(cos 4 theta+i sin 4 theta)^(-5))/((cos 3 theta+i sin 3 theta)^(-2)(cos 3 theta-i sin 3 theta)^(-9)) in the form of x+i y we get

Express (1-costheta+sin theta)/(1+cos theta + sin theta) in terms of tan theta//2 .