x-3y-02 1 -21 (B) lines + ly + 12 + 1 -6 Find the minimum distance. Between

Show that the lines (x-3)/(1)=(y-5)/(-2)=(z-7)/(1) and (x-1)/(7)=(y-1)/(6)=(z-1)/(7) are skew lines and find the shortest distance between them.

Find the perpendicular distances of the point (2,1) from the lines 8x+6y=17 and 4x+3y+1=0 and hence find the distance between the given lines.

Find the perpendicular distances of the point (2,1) from the parallel lines 3x-4y+4 = 0 and 4y-3x+5 = 0. Hence find the distance between them.

Points (1,-1,2) is the foot of perpendicular drawn from point (0,3,1) on the line (x-a)/l=(y-2)/3=(z-b)/4 find the shortest distance between this line and the line (x-1)/3=(y-2)/4=(z-3)/5

Consider the lines (x-3)/3=(y-8)/-1=(z-3)/1 and (x+3)/3=(y+7)/2=(z-6)/4 Find the shortest distance between the lines.

Let alpha be the distance between lines -x+y=2 and x-y=2 and beta be the distance between the lines 4x-3y=5 and 6y-8x=1, then

Let alpha be the distance between lines -x+y=2 and x-y=2 and beta be the distance between the lines 4x-3y= 5 and 6y-8x = 1 , then

Write the vector equation of the following lines and hence find distance between them (x-1)/(2)=(y-2)/(3)=(z+4)/(6),(x-3)/(4)=(y-3)/(6)=(z+5)/(12)

Let alpha be the distance between lines -x+y=2 and x-y=2 beta be the distance between the lines 4x-3y=5 and 6y-8x=1, then

Find the points on the line x + y = 1 that lie at a distance 3 units from the line 5x+12y = 3.