In a triangle `ABC,` the bisector of angle A meets the opposite side at D. Using vectors prove that `BD : DC = c : b`.

In triangle ABC, side AC is greater than side AB. If the internal bisector of angle A meets the opposite side at point D, prove that : angleADC is greater than angleADB .

In triangle ABC, side AC is greater than side AB. If the internal bisector of angle A meets the opposite side at point D, prove that : angleADC is greater than angleADB .

In a triangle ABC, angle bisector of angle BAC cut the side BC at D and meet the circumcircle of Delta ABC at E , then find AB .AC+DE. AE.

ABC is a right triangle such that AB=AC and bisector of angle C intersects the side AB at D. prove that AC+AD=BC.

ABC is a right triangle with AB = AC .If bisector of angle A meet BC at D then prove that BC = 2 AD .

ABC is a right triangle with AB = AC.If bisector of angle A meet BC at D then prove that BC =2 AD .

In a triangle ABC bisector of lfloor C meets the side AB at D and circum circle at E. The maximum value of CD×DE is