Find the equation of the circle which passes through the points `(2,-2)`, and (3,4) and whose centre lies on the line `x+y=2`.

Explanation

To find the equation of the circle that passes through the points (2, -2) and (3, 4) with its center lying on the line \( x + y = 2 \), we can follow these steps:

### Step 1: General Equation of the Circle
The general equation of a circle with center \((h, k)\) and radius \(r\) is given by:
\[ (x - h)^2 + (y - k)^2 = r^2 \]

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