[" 23."log_(81)243" fortic arlar "(1)/(6)?],[[" (a) "0.75," (b) "1.25]]

log_(1/3)81 =

log_(3)(1/81) =

What is log_(81)243 equal to ?

(log_(3)243)/(log_(2)sqrt(32))

Prove that "log" 2 + 16 "log" (16)/(15) + 12 "log " (25)/(24) + 7 "log"(81)/(80) = 1 .

The sum of the series log_(9)3+log_(27)3-log_(81)3+log_(243)3- ....... is a) 1-log_(e)2 b) 1+log_(e)2 c) log_(e)2 d) log_(e)3

If log _(12)81=x then find the value of log_(6)3