Home
Class 12
PHYSICS
[" The path followed by a body projected...

[" The path followed by a body projected along y axis is given "],[" by "y=sqrt(3)x-(1/2)x^(2)" .If "g=10m/s^(2)" then the initial "],[" velocity of projectile will be- "10m/s^(2)" then the initial "],[" (a) "3sqrt(10)m/s" (b) "2sqrt(10)m/s],[" (c) "10sqrt(3)m/s" (d) "10sqrt(2)m/s]

Promotional Banner

Similar Questions

Explore conceptually related problems

The path followed by a body projected along y axis is given by y=sqrt(3)x-(1//2)x^(2) . If g=10ms^(2) , then the initial velocity of projectile will be – (x and y are in m)

The trajectory of a projectile projected from origin is given by the equation y = x - (2x^(2))/(5) .The initial velocity of the projectile is

The trajectory of a projectile in a vertical plane is y=sqrt(3)x-2x^(2) . [g=10 m//s^(2)] Angle of projection theta is :-

The trajectory of a projectile in a vertical plane is y=sqrt(3)x-2x^(2) . [g=10 m//s^(2)] Angle of projection theta is :-

The trajectory of a projectile in a vertical plane is y=sqrt(3)x-2x^(2) . [g=10 m//s^(2)] Angle of projection theta is :-

The trajectory of a projectile projected from origin is given by the equation y=x-((2x^2)/5) . The initial velocity of the projectile is

The trajectory of a projectile in a vertical plane is y=sqrt(3)x-2x^(2) . [g=10 m//s^(2)] Range OA is :-

The trajectory of a projectile in a vertical plane is y=sqrt(3)x-2x^(2) . [g=10 m//s^(2)] Range OA is :-

The trajectory of a projectile in a vertical plane is y=sqrt(3)x-2x^(2) . [g=10 m//s^(2)] Range OA is :-

The trajectory of a projectile in a vertical plane is y=sqrt(3)x-2x^(2) . [g=10 m//s^(2)] Time of flight of the projectile is :-