" 13.Find the equation of tangent to "y=int_(x)^(x^(3))(dt)/(sqrt(1+t^(2)))" at "x=1

Find the equation of tangent to y=int_(x^(2))^(x^(3))(dt)/(sqrt(1+t^(2))) at x=1

Find the equation of tangent to y=int_(x^(2))^(x^(3))(dt)/(sqrt(1+t^(2))) at x=1 .

Find the equation of tangent to y=int_(x^2)^(x^3)(dt)/(sqrt(1+t^2))a tx=1.

Find the equation of tangent to y=int_(x^2)^(x^3)(dt)/(sqrt(1+t^2))a tx=1.

Find the equation of tangent to y=int_(x^2)^(x^3)(dt)/(sqrt(1+t^2))a tx=1.

equation of tangent to y=int_(x^(2)rarr x^(3))(dt)/(sqrt(1+t^(2))) at x=1 is:

Equation of the tangent to y= int_(x^(2))^(x^(3)) (dt)/(sqrt(1+t^(2))) at x=1 is

The equation of tangent to the curve y=int_(x^(2))^(x^(3))(dt)/(sqrt(1+t^(2))) at x=1 is sqrt(3)x+1=y (b) sqrt(2)y+1=x sqrt(3)x+y=1(d)sqrt(2)y=x

The equation of the tangent to the curve y= int_(x^4)^(x^6) (dt)/( sqrt( 1+t^2) ) at x=1 is