5tan theta=4 pi(5sin theta-3cos theta)/(5sin theta+2cos theta)

If theta lies in the first quadrant and 5tan theta=4 then (5sin theta-3cos theta)/(sin theta+2cos theta)=

If 5tan theta=4, then (5sin theta-3cos theta)/(5sin theta+2cos theta) is equal to 0 (b) 1 (c) (1)/(6)(d)6

if 5cot theta=4, then the value of ((5sin theta-3cos theta)/(sin theta+2cos theta))

If 5 tan theta = 4 , show that ( 5 sin theta - 3 cos theta)/(5 sin theta + 3 cos theta) = (1)/(7)

If 5 tan theta = 4 , show that ( 5 sin theta - 3 cos theta)/(5 sin theta + 3 cos theta) = (1)/(7)

If 5tan theta-4=0, then the value of (5sin theta-4cos theta)/(5sin theta+4cos theta) is (5)/(3)(b)(5)/(6)(c)0(d)(1)/(6)

If 3 cot theta = 5, then (5 sin theta - 3 cos theta)/(5 sin theta + 3 cos theta)